polars.internals.expr.ExprStringNameSpace.replace¶

ExprStringNameSpace.replace(pattern: str, value: str) → polars.internals.expr.Expr¶

Replace first regex match with a string value.

Parameters

pattern: Regex pattern.
value: Replacement string.

Examples

>>> df = pl.DataFrame({"id": [1, 2], "text": ["123abc", "abc456"]})
>>> df.with_column(pl.col("text").str.replace(r"abc", "ABC"))
shape: (2, 2)
┌─────┬────────┐
│ id  ┆ text   │
│ --- ┆ ---    │
│ i64 ┆ str    │
╞═════╪════════╡
│ 1   ┆ 123ABC │
├╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
│ 2   ┆ abc456 │
└─────┴────────┘

polars.internals.expr.ExprStringNameSpace.split_exact polars.internals.expr.ExprStringNameSpace.replace_all